Sort array of numbers by number of ones in binary representation

sort.js

function compareByNumOfOnes(a, b) {
    return a.match(/1/g).length - b.match(/1/g).length;
}

function solution(array) {
    return array.map(item => item.toString(2))
                .sort(compareByNumOfOnes)
                .map(item => parseInt(item, 2))
}


// Example
// [1, 2, 4, 3] === solution([1, 2, 3, 4])

console.log(solution([1, 2, 3, 4]));