How we can make methods of observable via other methods

index.js

const flatMapLatest = (fn, stream) => 
    stream.publish(s => s.flatMap(v => fn(v).takeUntil(s)));

const flatMapLatest = (fn, stream, resultSelector) => stream.publish(s => {
    return s.flatMap(v => fn(v).map(v2 => resultSelector(v, v2)).takeUntil(s));
});

const delay = (source, delay) => source.flatMap(e => Rx.Observable.timer(delay).mapTo(e))

const debounceTime = (time, stream) => flatMapLatest(v => of(v).delay(time), stream);

const debounce = (other, stream) => flatMapLatest(v => other().take(1).mapTo(() => v), stream);

const sample = (sampler, source) => 
            source[typeof sampler === 'number' ? 'bufferTime' : 'buffer'](sampler).map(values => last(values));


const sample2 = (sampler, source) => create(o => {
  return new CompositeDisposable(
    (source = source.publish(), sampler.flatMap(() => source.take(1)).subscribe(o)),
    source.connect()
  );
});

const sample3 = (sampler, source) => source.publish(src => sampler.flatMap(() => src.take(1)));

const window$ = (source, windowBoundry) => {
  source = source.publish();
  const s = source.let(src => windowBoundry
  .startWith(0)
  .map(
    src.takeUntil(windowBoundry)
  ));

  source.connect();

  return s;
}

const flatMapFirst$ = (source, fn) => source.publish(src => {
  var free = true;
  return src.filter(_ => free).map(fn).do(_ => free = false).switchMap(el => {
    return el.finally(() => free = true);
  });
});


const throttleTime = (source, delay) => source.flatMapFirst(e =>
  of(e).concat(
    timer(delay).filter(_ => false);
));            

const throttle = (source, other) => source.flatMapFirst(e =>
  of(e).concat(
    other.take(1).filter(_ => false);
));

const interval = (delay) => Rx.Observable.timer(delay, delay)

const intervalQuick = (delay) => Rx.Observable.timer(0, delay)

const filter = (source, f) => source.flatMap(e => f(e) ? e : empty)

const map (source, f) => source.flatMap(e => of(f(e)))

const startWith = (source, el) => concat(of(el), source)

const concat = (source1, source2) => source1.merge(source1.last().flatMap(e => source2)