Color harmony algorithm

color_algo

public static List GenerateColors_Harmony(
   int colorCount,
   float offsetAngle1,
   float offsetAngle2,
   float rangeAngle0,
   float rangeAngle1,
   float rangeAngle2,
   float saturation, float luminance)
{
   List colors = new List();

   float referenceAngle = random.NextFloat() * 360;

   for (int i = 0; i < colorCount; i++)
   {
      float randomAngle = 
         random.NextFloat() * (rangeAngle0 + rangeAngle1 + rangeAngle2);

      if (randomAngle > rangeAngle0)
      {
         if (randomAngle < rangeAngle0 + rangeAngle1)
         {
            randomAngle += offsetAngle1;
         }
         else
         {
            randomAngle += offsetAngle2;
         }
      }

      HSL hslColor = new HSL(
         ((referenceAngle + randomAngle) / 360.0f) % 1.0f,
         saturation, 
         luminance);

      colors.Add(hslColor.Color);
   }

   return colors;
}

This great article http://devmag.org.za/2012/07/29/how-to-choose-colours-procedurally-algorithms/ had this implementation.
I have pending to port the algo to javascript and use it on potaje.
The article is down now due to the account being suspended, which is sad because it was a great article.

This one takes three colors and create a pallete out of them.

public static Color RandomMix(Color color1, Color color2, Color color3,
float greyControl)
{
int randomIndex = random.NextByte() % 3;

  float mixRatio1 =
     (randomIndex == 0) ? random.NextFloat() * greyControl : random.NextFloat();

  float mixRatio2 = 
     (randomIndex == 1) ? random.NextFloat() * greyControl : random.NextFloat();

  float mixRatio3 = 
     (randomIndex == 2) ? random.NextFloat() * greyControl : random.NextFloat();

  float sum = mixRatio1 + mixRatio2 + mixRatio3;

  mixRatio1 /= sum;
  mixRatio2 /= sum;
  mixRatio3 /= sum;

  return Color.FromArgb(
     255,
     (byte)(mixRatio1 * color1.R + mixRatio2 * color2.R + mixRatio3 * color3.R),
     (byte)(mixRatio1 * color1.G + mixRatio2 * color2.G + mixRatio3 * color3.G),
     (byte)(mixRatio1 * color1.B + mixRatio2 * color2.B + mixRatio3 * color3.B));

}