Created
January 7, 2015 15:06
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トランザクションの問題の確認用
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using System; | |
using System.Linq; | |
using System.Collections.Generic; | |
using System.Console; | |
namespace twinkfrag.Transaction | |
{ | |
class Transaction | |
{ | |
public static void Main(string[] args) | |
{ | |
List<string> item = new List<string>() | |
{ | |
"A", "B", "C", "D", "E" | |
}; | |
List<string> hoge = new List<string>() | |
{ | |
"ABC", | |
"ABC", | |
"", | |
"", | |
"", | |
"", | |
"", | |
"", | |
"DE", | |
"DE", | |
}; | |
foreach (var c1 in item) | |
{ | |
foreach (var c2 in item.Where(x => x != c1)) | |
{ | |
var c1Contain = hoge.FindAll(x => x.Contains(c1)).Count; | |
var c12Contain = hoge.FindAll(x => x.Contains(c1) && x.Contains(c2)).Count; | |
if (c12Contain > 1) | |
{ | |
if ((Double)c12Contain / c1Contain > 0.7) Write("> "); | |
WriteLine("{0} => {1}: {2}", c1, c2, (Double)c12Contain / c1Contain); | |
} | |
} | |
} | |
foreach (var c1 in item) | |
{ | |
foreach (var c2 in item.Where(x => x != c1)) | |
{ | |
foreach (var c3 in item.Where(x => x != c1 && x != c2)) | |
{ | |
var c1Contain = hoge.FindAll(x => x.Contains(c1)).Count; | |
var c12Contain = hoge.FindAll(x => x.Contains(c1) && x.Contains(c2)).Count; | |
var c123Contain = hoge.FindAll(x => x.Contains(c1) && x.Contains(c2) && x.Contains(c3)).Count; | |
if (c123Contain > 1) | |
{ | |
if ((Double)c123Contain / c12Contain > 0.7) Write("> "); | |
WriteLine("{0}, {1} => {2}: {3}", c1, c2, c3, (Double)c123Contain / c12Contain); | |
} | |
} | |
} | |
} | |
} | |
} | |
} |
TID | アイテム集合 |
---|---|
1 | {A,B,C} |
2 | {A,B,C,E} |
3 | {D,E} |
4 | {A,D,E} |
5 | {B,E} |
6 | {A,C} |
7 | {B,C} |
8 | {A} |
9 | {B} |
10 | {C} |
これでいい感じに命題満たせました()
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A, Bが両方入っているものには必ずCも入れる
Dが入っているものには必ずEも入れる
これを2レコードずつで支持度0.2,確信度1.0
あとは他の確信度がばらけるように適当に突っ込む.最後の2つみたいに{D, E}にそれぞれAとBとか入れるとA->DやD->Bなんかがばらけていい感じな気がする
(適当)