Created
July 9, 2013 13:37
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Calculate the probability that two people in a given group will have the same first initial and last name.
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#!/usr/bin/env ruby | |
# Get name file from https://www.census.gov/genealogy/www/data/1990surnames/names_files.html | |
names = File.readlines('dist.male.first.txt') | |
list = {} | |
letters = ('A'..'Z') | |
total_people = 40000 | |
last_name_freq = 0.01006 # Smith | |
letters.each do |letter| | |
list[letter] = [] | |
names.each do |line| | |
if line.match("^#{letter}") | |
list[letter] += [line[15...20].to_f] | |
end | |
end | |
frequency = list[letter].inject(:+) | |
probabilty = 1.0 | |
number_of_people = (frequency * total_people / 100 * last_name_freq).to_i | |
number_of_people.times do |i| | |
probabilty *= (10000.0 - i)/10000.0 | |
end | |
p "#{letter}: #{1 - probabilty}" | |
end |
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