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July 12, 2021 09:00
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AtCoder Beginner Contest 174 [ C - Repsept ] https://atcoder.jp/contests/abc174/tasks/abc174_c
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''' | |
[問題] | |
https://atcoder.jp/contests/abc174/tasks/abc174_c | |
[解法] | |
https://youtu.be/h0MGG8rxrYc?t=1654 | |
数列 7, 77, 777, 7777, ....は | |
漸化式 *10+7 で表現できる。 | |
これはmod(余り)をとった値でも同様。 | |
7%K の次の77%K も *10+7の関係にある。 | |
それを利用して、K回この処理を繰り返せば、とりうる余りは1ループする。 | |
この余りのループの中に0があれば、それがKの倍数 | |
こんなん、説明されなきゃ絶対わからん(^^; | |
''' | |
import sys | |
sys.setrecursionlimit(10 ** 6) # 再帰上限の引き上げ | |
input = sys.stdin.readline | |
INF = 2 ** 63 - 1 | |
K = int(input()) | |
x = 7%K | |
for i in range(1,K + 1): | |
if x == 0: | |
print(i) | |
exit() | |
x = (x*10+7)%K | |
print(-1) |
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