Created
July 6, 2021 07:25
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AtCoder Beginner Contest 172 [ D - Sum of Divisors ] https://atcoder.jp/contests/abc172/tasks/abc172_d
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''' | |
[問題] | |
https://atcoder.jp/contests/abc172/tasks/abc172_d | |
[参考] | |
https://youtu.be/v8ppNGf49Nk?t=6627 | |
snukeさん解説放送。 | |
ここで解説されている方法に基づいて実装。 | |
''' | |
import sys | |
sys.setrecursionlimit(10 ** 6) # 再帰上限の引き上げ | |
input = sys.stdin.readline | |
INF = 2 ** 63 - 1 | |
N = int(input()) | |
# f[i] にiの約数の数を保存する配列を作成。どの数も1の倍数ではあるので、1で初期化 | |
f = [1] * (N + 1) | |
f[0] = 0 # 0の倍数は0にしとく。使ってないけど | |
# iの倍数を1ずつカウントアップしていく。この計算量はO(logN)くらい。調和級数とのこと。 | |
for i in range(2, (N + 1)): | |
for j in range(i, (N + 1), i): | |
f[j] += 1 | |
# k * f[k] を k=1〜N までの範囲で全合計する | |
ans = 0 | |
for k in range(1, (N + 1)): | |
ans += k * f[k] | |
print(ans) |
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