liduo

liduo

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>

void fun(FILE *stdin) {
	char str[20], tmp[20];
	int sum, len, i, idx, cnt;
	int a1[10], num1 = 0, num2 = 0, ans1 = 0;
	double a2[10], ans2 = 0;
	while(scanf("%s", str) != EOF) {
		len = strlen(str);
		sum = 0;
		cnt = 0;
		idx = -1;
		for(i = 0; i < len; ++i) {
			if(str[i] > '0' && str[i] <= '9') {
				sum = sum * 10 + str[i] - '0';
				++cnt;
			}
			else if(str[i] == '.')
				idx = cnt;
		}
		if(idx == -1) {
			a1[++num1] = sum;
			if(str[0] == '-')
				a1[num1] = -a1[num1];
		}
		else {
			a2[++num2] = sum * 1.0;
			for(i = 1; i <= cnt - idx; ++i)
				a2[num2] /= 10;
			if(str[0] == '-')
				a2[num2] = -a2[num2];
		}
	}
	printf("整型有：");
	for(i = 1; i <= num1; ++i) {
		printf("%d ", a1[i]);
		ans1 += a1[i];
	}
	printf("\n和为：");
	printf("%d\n", ans1);
	printf("浮点数：");
	for(i = 1; i <= num2; ++i) {
		printf("%lf ", a2[i]);
		ans2 += a2[i];
	}
	printf("\n和：");
	printf("%f\n", ans2);
	return 0;

}


int main() {
	freopen("tmp", "r", stdin);
	fun(stdin);
	
	return 0;
}