find amount of smallest unit length closed intervals in javascript

findAmountOfSmallestUnitLengthClosedIntervals.js

export default function findAmountOfSmallestUnitLengthClosedIntervals(sortedPoints) {
    if(sortedPoints.length <= 1) return 1;

    let amount = 0;
    for (let i = 0, len = sortedPoints.length - 1; i < len;) {
        let unitClosed = false;
        for (let z = i + 1; z < sortedPoints.length; z++) {
            if (sortedPoints[z] - sortedPoints[i] < 1) {
                unitClosed = true;
                if (z === sortedPoints.length - 1) {
                    i = z;
                    amount += 1;
                    break;
                }
            } else if (sortedPoints[z] - sortedPoints[i] === 1) {
                amount += 1;
                i = z + 1;
                break;
            } else {
                amount += 1;
                i = z;
                if (z === sortedPoints.length - 1) amount += 1;
                break;
            }
        }
    }

    return amount;
}

// Example of usage
// const sortedPoints = [
//     1,
//     9,
//     9.009,
//     9.1,
//     9.5,
//     9.8,
//     100
// ]

// console.log(findAmountOfSmallestUnitLengthClosedIntervals(sortedPoints));