Created
November 20, 2012 08:03
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UVA 104 : Arbitrage
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#include <iostream> | |
#include <stack> | |
using namespace std; | |
static const int MAX_SIZE = 20; | |
struct Cell { | |
double profit; // the best profit so far | |
int action; // index to the currency that yields the current profit | |
} Profits[MAX_SIZE][MAX_SIZE][MAX_SIZE]; | |
int main() { | |
int n; // dimension | |
bool bHasMadeProfit; | |
while ( cin >> n ) { | |
bHasMadeProfit = false; | |
// clear the table | |
for ( int i=0; i<n; i++ ) { | |
for ( int j=0; j<n; j++ ) { | |
for ( int k=0; k<n; k++ ) { | |
Profits[i][j][k].profit = 0.0; | |
Profits[i][j][k].action = -1; | |
} | |
} | |
} | |
// init table | |
for ( int r=0; r<n; r++ ) { | |
for ( int c=0; c<n; c++ ) { | |
if ( c != r) { | |
cin >> Profits[0][r]1.profit = 1.0; | |
} | |
} | |
} | |
for ( int trial = 1; trial < n; trial++ ) { | |
for ( int r=0; r<n; r++ ) { | |
for ( int c=0; c<n; c++ ) { | |
// find the max profit from currency r to currency c | |
for ( int k=0; k<n; k++ ) { | |
double val = Profits[trial-1][r][k].profit * Profits[0][k]1.profit < val) { | |
Profits[trial][r]1.action = k; | |
} | |
} | |
} | |
if ( Profits[trial][r][r].profit > 1.01 ) { | |
bHasMadeProfit = true; | |
// backtracking | |
stack<int> outsequence; | |
outsequence.push(r); // add another action | |
int prevAction = Profits[trial][r][r].action; | |
for ( int step = trial-1; step>=0; step-- ) { | |
outsequence.push(prevAction); | |
prevAction = Profits[step][r][prevAction].action; | |
} | |
//print the first action ( choosing currency r ) | |
cout << r + 1; | |
while ( ! outsequence.empty() ) { | |
cout << " " << outsequence.top() + 1; | |
outsequence.pop(); | |
} | |
cout << endl; | |
break; | |
} // end of c-loop | |
} // end of r-loop | |
if ( bHasMadeProfit ) { | |
break; | |
} | |
} // end trial for-loop | |
if ( ! bHasMadeProfit ) { | |
cout << "no arbitrage sequence exists" << endl; | |
} | |
} // end while | |
return 0; | |
} |
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