Created
January 30, 2012 03:59
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Script to copy an image to clipboard
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import win32api, sys | |
import Image | |
import win32clipboard | |
from cStringIO import StringIO | |
def send_to_clipboard(clip_type, data): | |
win32clipboard.OpenClipboard() | |
win32clipboard.EmptyClipboard() | |
win32clipboard.SetClipboardData(clip_type, data) | |
win32clipboard.CloseClipboard() | |
if __name__ == '__main__': | |
# get the file and verify PIL can open it | |
try: | |
image = Image.open(sys.argv[1]) | |
except IOError, e: | |
win32api.MessageBox(0, 'Cannot open %s: %s' % | |
(sys.argv[1], str(e)), | |
'Copy Image to Clipboard') | |
output = StringIO() | |
# convert the file | |
try: | |
image.convert("RGB").save(output, "BMP") | |
except Exception, e: | |
win32api.MessageBox(0, 'Cannot convert %s to Bitmap: %s' % | |
(sys.argv[1], str(e)), | |
'Copy Image to Clipboard') | |
data = output.getvalue()[14:] | |
output.close() | |
send_to_clipboard(win32clipboard.CF_DIB, data) |
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