java.net http post request

Javanet.post.java

String url = "http://localhost/actions/api/file/addFile";
    URL obj = new URL(url);
    HttpURLConnection con = (HttpURLConnection) obj.openConnection();

    //add reuqest header
    con.setRequestMethod("POST");
    con.setRequestProperty("User-Agent", "google chrome");
    con.setRequestProperty("Accept-Language", "en-US,en;q=0.5");

    StringBuilder urlParameters = new StringBuilder();
    urlParameters.append("file_id=").append("27FF7426A59C4FE8AC4CF94535D2B2E1")
    .append("&")
    .append("file_type=").append("DRIVER").append("&file_base64=").append(URLEncoder.encode(Base64.encodeBase64String(binaryData),"utf-8"));
   // String query = URLEncoder.encode(urlParameters.toString(), "UTF-8");
    // Send post request
    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters.toString());
    wr.flush();
    wr.close();

    int responseCode = con.getResponseCode();
    System.out.println("\nSending 'POST' request to URL : " + url);
    System.out.println("Post parameters : " + urlParameters);
    System.out.println("Response Code : " + responseCode);

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();

    //print result
    System.out.println(response.toString());

接收端只要按照正常的request.getParameter("xx")处理就行