smtp displayname python

smtpdisplayname.py

#send html email

from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.header import Header
from email.utils import formataddr

msg = MIMEMultipart('alternative')
msg['From'] = formataddr((str(Header('MyWebsite', 'utf-8')), '[email protected]'))
msg['To'] = '[email protected]'

html = "email contents"

# Record the MIME types of text/html.
msg.attach(MIMEText(html, 'html'))

# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')

# sendmail function takes 3 arguments: sender's address, recipient's address
# and message to send - here it is sent as one string.
s.sendmail('[email protected]', '[email protected]', msg.as_string())
s.quit()

Tks

Thanks, was having issues displaying the from address correctly!

The str(Header(...)) casting seems completely redundant.
This works fine:

msg['From'] = formataddr(('MyWebsite', '[email protected]'))

The formataddr defaults to using Unicode.

As far as s.sendmail('[email protected]', '[email protected]', msg.as_string()), you are hardcoding things twice.
Use the s.send_message(msg) instead.

The str(Header(...)) casting seems completely redundant.
This works fine:

msg['From'] = formataddr(('MyWebsite', '[email protected]'))

The formataddr defaults to using Unicode.

As far as s.sendmail('[email protected]', '[email protected]', msg.as_string()), you are hardcoding things twice.
Use the s.send_message(msg) instead.

This works perfectly.
Thanks to both.

Thank you!