Super long sums

10013.c

/* Solution to the UVa Online Judge problem no. 10013 */

#include <stdlib.h>
#include <stdio.h>

#define MAX_SIZE 1000000


char buffer[4 * MAX_SIZE],
     number[MAX_SIZE];

int main() {
	int n, m, i, j, tmp, carry;
	if (scanf("%d", &n) != 1) {
		return 0;
	}

	number[0] = '1';
	for (i = 0; i < n; i++) {
		if (scanf("%d\n", &m) != 1) {
			return 0;
		}

		buffer[0] = 0;
		if (fread(buffer, 1, m * 4, stdin) == -1) {
			return 0;
		}
		buffer[m * 4] = 0;

		for (number[m + 2] = carry = 0, j = 1; j <= m; j++) {
			tmp = buffer[4*(m-j)] + buffer[4*(m-j)+2] - 48 + carry;
			carry = tmp > 57;
			number[m - j + 1] = carry ? tmp - 10 : tmp;
		}

		number[m + 1] = '\n';
		if (fwrite(number + 1 - carry, 1, m + 1 + carry, stdout) == 0) {
			return 0;
		}

		if (i < (n - 1)) {
			printf("\n");
		}
	}

	return 0;
}

10013.rb

#!/usr/bin/env ruby

def line_nums
	begin
		l = gets.strip!
	end while l.empty?

	l.to_i
end

def add_numbers(lines)
	buffer = STDIN.read lines * 4

	number = []
	carry = false
	(lines - 1).downto 0 do |i|
		a = buffer[4 * i].chr.to_i
		b = buffer[4 * i + 2].chr.to_i
		
		c = a + b
		c += 1 if carry 
		
		number[i] = c % 10

		carry = c > 9
	end	

	if carry
		number.unshift 1
	end

	number
end

def print_number(number)
	puts number.join('')
end

if __FILE__ == $0
	n = gets
	n.to_i.times do |i|
		print_number add_numbers line_nums
		puts if i < n.to_i - 1
	end
end