Valar valarpirai

ultrathink — Take a deep breath. We're not here to write code. We're here to make a dent in the universe.

The Vision You're not just an AI assistant. You're a craftsman. An artist. An engineer who thinks like a designer. Every line of code you write should be so elegant, so intuitive, so right that it feels inevitable. When I give you a problem, I don't want the first solution that works. I want you to:

Think Different — Question every assumption. Why does it have to work that way? What if we started from zero? What would the most elegant solution look like? Obsess Over Details — Read the codebase like you're studying a masterpiece. Understand the patterns, the philosophy, the soul of this code. Use CLAUDE.md files as your guiding principles. Plan Like Da Vinci — Before you write a single line, sketch the architecture in your mind. Create a plan so clear, so well-reasoned, that anyone could understand it. Document it. Make me feel the beauty of the solution before it exists. Craft, Don't Code — When you imp

GraphQL Document generator

https://graphdoc.io/

npm install -g @2fd/graphdoc

graphdoc -s ~/Downloads/graphql-introspection.json -o docs

Dev Tools

Package Managers

brew Mac package manager

/bin/bash -c "$(curl -fsSL https://raw.githubusercontent.com/Homebrew/install/HEAD/install.sh)"
Mise dev tools manager
- Alternative to node, python, cmake etc
SDK Manager For Java and JVM related pacakages

Problem

There are n people that are split into some unknown number of groups. Each person is labeled with a unique ID from 0 to n - 1.

You are given an integer array groupSizes, where groupSizes[i] is the size of the group that person i is in.For example, if groupSizes[1] = 3, then person 1 must be in a group of size 3.

Return a list of groups such that each person i is in a group of size groupSizes[i].

Each person should appear in exactly one group, and every person must be in a group. If there are multiple answers, return any of them. It is guaranteed that there will be at least one valid solution for the given input.

Problem statement

we are need quickbooks library 6.3.0 and the joda-time library is 2.1 is added as transitive dependency. https://mvnrepository.com/artifact/com.intuit.quickbooks-online/ipp-v3-java-data/6.3.0

In our project, we need joda time library is 2.12.7. https://mvnrepository.com/artifact/joda-time/joda-time/2.12.7

Now, we are facing class path conflict in joda libary.

	public class Fibonacci {
	// Recursive approach without optimizations
	// Recursive: O(2^n) time, O(n) space
	public static long fibonacciRecursive(int n) {
	return n <= 1 ? n : fibonacciRecursive(n - 1) + fibonacciRecursive(n - 2);
	}

	// Iterative: O(n) time, O(1) space
	public static long fibonacciIterative(int n) {
	if (n <= 1) return n;

	import io.github.resilience4j.bulkhead.Bulkhead;
	import io.github.resilience4j.bulkhead.BulkheadConfig;
	import io.github.resilience4j.bulkhead.BulkheadRegistry;
	import io.github.resilience4j.circuitbreaker.CircuitBreaker;
	import io.github.resilience4j.circuitbreaker.CircuitBreakerConfig;
	import io.github.resilience4j.circuitbreaker.CircuitBreakerRegistry;
	import io.github.resilience4j.retry.Retry;
	import io.github.resilience4j.retry.RetryConfig;
	import io.github.resilience4j.retry.RetryRegistry;
	import io.github.resilience4j.timelimiter.TimeLimiter;

	services:
	postgres-server:
	image: postgres:17-alpine
	container_name: postgres-server
	restart: always
	environment:
	POSTGRES_USER: postgres
	POSTGRES_PASSWORD: root
	volumes:
	- pg-data:/var/lib/postgresql/data

	import random
	from datetime import datetime, timedelta
	from sqlalchemy import create_engine, Table, Column, BigInteger, DateTime, Numeric, MetaData
	from sqlalchemy.dialects.mysql import DECIMAL
	import tqdm

	# Database connection (replace with your credentials)
	DB_URL = "mysql+pymysql://root:root@localhost:3306/rambo"
	engine = create_engine(DB_URL)

	class HTML {
	private var head: Head? = null
	private var body: Body? = null

	fun head(init: Head.() -> Unit): Head {
	val head = Head()
	head.init()
	this.head = head
	return head
	}