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@valdergallo
Created September 29, 2016 19:08
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Sudoku AI
n = 3 # Size of inner region
n2, n3, n4 = n**2, n**3, n**4
def show(flatline):
'Display grid from a string (values in row major order with blanks for unknowns)'
fmt = '|'.join(['%s' * n] * n)
sep = '+'.join(['-' * n] * n)
for i in range(n):
for j in range(n):
offset = (i*n+j)*n2
print fmt % tuple(flatline[offset:offset+n2])
if i != n-1:
print sep
def _find_friends(cell):
'Return tuple of cells in same row, column, or subgroup'
friends = set()
row, col = cell // n2, cell % n2
friends.update(row * n2 + i for i in range(n2))
friends.update(i * n2 + col for i in range(n2))
nw_corner = row // n * n3 + col // n * n
friends.update(nw_corner + i + j for i in range(n) for j in range(0, n3, n2))
friends.remove(cell)
return tuple(friends)
friend_cells = map(_find_friends, range(n4))
def select_an_unsolved_cell(possibles, heuristic=min):
# Default heuristic: select cell with fewest possibilities
# Other possible heuristics include: random.choice() and max()
return heuristic((len(p), cell) for cell, p in enumerate(possibles) if len(p)>1)[1]
def solve(possibles, pending_marks):
# Apply pending_marks (list of cell,value pairs) to possibles (list of str).
# Mutates both inputs. Return solution as a flat string (values in row-major order)
# or return None for dead-ends where all possibilites have been eliminated.
for cell, v in pending_marks:
possibles[cell] = v
for f in friend_cells[cell]:
p = possibles[f]
if v in p:
p = possibles[f] = p.replace(v, '') # exclude value v from friend f
if not p:
return None # Dead-end: all possibilities eliminated
if len(p) == 1:
pending_marks.append((f, p[0]))
# Check to see if the puzzle is fully solved (each cell has only one possible value)
if max(map(len, possibles)) == 1:
return ''.join(possibles)
# If it gets here, there are still unsolved cells
cell = select_an_unsolved_cell(possibles)
for v in possibles[cell]: # try all possible values for that cell
ans = solve(possibles[:], [(cell, v)])
if ans is not None:
return ans
# ----- Examples -----
for given in [
'53 7 6 195 98 6 8 6 34 8 3 17 2 6 6 28 419 5 8 79',
' 75 4 5 8 17 6 36 2 7 1 5 1 1 5 8 96 1 82 3 4 9 48 ',
' 9 7 4 1 6 2 8 1 43 6 59 1 3 97 8 52 7 6 8 4 7 5 8 2 ',
'67 38 921 85 736 1 8 4 7 5 1 8 4 2 6 8 5 175 24 321 61 84',
'27 15 8 3 7 4 7 5 1 7 9 2 6 2 5 8 6 5 4 8 59 41',
]:
show(given)
pending_marks = [(i, v) for i, v in enumerate(given) if v != ' ']
possibles = ['123456789'] * len(given)
result = solve(possibles, pending_marks)
print
show(result)
print '=-' * 20
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