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##Exercise: ModulesAndFunctions-6 | |
defmodule Chop do | |
def guess(actual, lo..hi) when (lo <= hi) and (actual in lo..hi) do | |
current = guessing(lo, hi) | |
IO.puts "Is it #{current}" | |
guess(current, actual, lo..hi) | |
end | |
defp guess(value, actual, _) when value == actual, do: IO.puts value | |
defp guess(value, actual, lo.._) when actual < value, do: guess actual, lo..(value - 1) | |
defp guess(value, actual, _..hi) when actual > value, do: guess actual, (value + 1)..hi | |
defp guessing(lo, hi), do: lo + div(hi - lo, 2) | |
end | |
Chop.guess 273, 1..1000 | |
# Is it 500 | |
# Is it 250 | |
# Is it 375 | |
# Is it 312 | |
# Is it 281 | |
# Is it 265 | |
# Is it 273 | |
# 273 |
Nicely said ๐ . It is good to see more and more people coming to Elixir from Ruby
hey @veelenga, your solution really helped me. I'm coming from 15 years of ruby and it is hard to wrap my old brain around new ideas.
But what's up with this? Doesn't your solution do this? What am I misunderstanding? Or is it because your defp functions have 3 params so it is considered totally different?
@pdbradley yes, the signature of def
and defp
functions are different, so they are valid.
Keep in mind, that solution was written 3 years ago, when the language was slightly different :)
I am a newbie in Elixir coming from Ruby. I'd written my solution for this but I felt like it could be better and then I came across your solution. Brilliant! I'd never thought about matching that range as lo..hi
in the function head, I was still doing the matching in the function body. ๐ I was also doing the guessing in each of the functions separately, your code helped me learn a lot!
Hello, @veelenga ! Although your solution works, I would like to make a couple of notes:
- An extra work for the given exercise;
- Both your solution and the book author's solution use private functions,
which seems unfair to me, since this is the topic of the next section.
Thus, the solution can be rewritten as follows:
defmodule Chop do
def guess(actual, low..high) do
guessed = div(low + high, 2)
IO.puts "Is it #{guessed}"
processing_guessed =
fn
n when n == actual -> IO.puts n
n when n > actual -> guess actual, low..(n - 1)
n when n < actual -> guess actual, (n + 1)..high
end
processing_guessed.(guessed)
end
end
I've been reading the book, and this solution was such an "a-ha!" moment for me when I looked at your pattern matching in the function signature:
def guess(actual, lo..hi) when (lo <= hi) and (actual in lo..hi) do
. I know that pattern matching instead of control flow is a central idea in Elixir, but coming from Ruby, it's been hard to understand. This example really showcased that language feature. Thanks!