React Router V4 Redirect after form submission

app.js

import React, { Component } from 'react'
import { Redirect } from 'react-router'

export default class ContactForm extends Component {
  constructor () {
    super();
    this.state = {
      fireRedirect: false
    }
  }
  
  submitForm = (e) => {
    e.preventDefault()
    this.setState({ fireRedirect: true })
  }
  
  render () {
    const { from } = this.props.location.state || '/'
    const { fireRedirect } = this.state
    
    return (
      <div>
        <form onSubmit={this.submitForm}>
          <button type="submit">Submit</button>
        </form>
        {fireRedirect && (
          <Redirect to={from || '/thank-you'}/>
        )}
      </div>
    )
    
  }
}

Thanks 😄 🔝

thanks!!!

If you are using redux-saga to manage your side effects and api calls, I would suggest doing this in the saga.

Why? Keeps your component clean and you don't need to keep a state in your component just for the redirect.

I.e. Steps:

1. Submit a form
2. Dispatch action
3. Saga listens for the action, and calls the api
4. On success, redirect to wherever you want.

Code:

function* createInvoice(action) {
  try {
    const response = yield call(axios.post, COMMAND_INVOICES_URL, action.data);
    yield put(invoiceCreated());
    yield put(push(`/invoice/${response.data}`));
  } catch (err) {
    yield put(invoiceFailed(err));
  }
}

thank you :)

@verticalgrain thank you so much.much applauded.

verticalgrain@ thanks a lot it saved my day

Thanks! Very clean solution!

Thank you!!!!

I think this is another solution. Since there are there elemnet that router provides which are match, location adn history, we may push any route to history. considering rerouting after submiting a form:
{history} = this.props <button onClick={this.onFormSubmit(formValues, history)} )> Submit <button/> ( onFormSubmit(formValues, history) { database.post(formValues) (some codes) history.push('/') } )

nice one