Element with left side smaller and right side greater in Ruby

elements.rb

arr = [1,2,10,43,20,80,90]

maxArr = []
minArr = []
solution = [] #
large = arr[0] #first element
small = arr[-1] #last element

arr.each_with_index do |num, index|
  if arr[index] > large
    large = arr[index]
  end
  maxArr[index] = large
end

reverse_index = 5
arr.reverse_each do |num|
  if arr[reverse_index] < small
    small = arr[reverse_index]
  end
  minArr[reverse_index] = small
  reverse_index -= 1
end

arr.each_with_index do |num, index|
  # Skip first and last element if the array.
  if index != 0 && index != (arr.size - 1)
    if minArr[index] == maxArr[index]
      solution << minArr[index]
    end
  end
end

puts solution

# Time Complexity => O(n)