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/* | |
Copyright 2018 Viktor Klang | |
Licensed under the Apache License, Version 2.0 (the "License"); | |
you may not use this file except in compliance with the License. | |
You may obtain a copy of the License at | |
http://www.apache.org/licenses/LICENSE-2.0 | |
Unless required by applicable law or agreed to in writing, software | |
distributed under the License is distributed on an "AS IS" BASIS, | |
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | |
See the License for the specific language governing permissions and | |
limitations under the License. | |
*/ | |
import scala.concurrent._ | |
import java.util.concurrent.CancellationException | |
final class Interrupt extends (() => Boolean) { | |
private[this] final var state: AnyRef = null | |
override final def apply(): Boolean = this.synchronized { | |
state match { | |
case null => | |
state = this | |
true | |
case _: this.type => false | |
case t: Thread => | |
state = this | |
t.interrupt() | |
true | |
} | |
} | |
private[this] final def enter(): Boolean = | |
this.synchronized { | |
state match { | |
case _: this.type => false | |
case null => | |
state = Thread.currentThread | |
true | |
} | |
} | |
private[this] final def exit(): Boolean = | |
this.synchronized { | |
state match { | |
case _: this.type => false | |
case t: Thread => | |
state = this | |
true | |
} | |
} | |
def interruptibly[T](body: =>T): T = | |
if (enter()) { | |
try body catch { | |
case ie: InterruptedException => throw new CancellationException() | |
} finally { | |
if(!exit() && Thread.interrupted()) | |
() // If we were interrupted and flag was not cleared | |
} | |
} else throw new CancellationException() | |
} | |
def interruptibly[T](body: => T)(implicit ec: ExecutionContext): (Future[T], () => Boolean) = { | |
val interrupt = new Interrupt() | |
(Future(interrupt.interruptibly(body))(ec), interrupt) | |
} |
This is the only way to cancel future I found :)
But I can't figure out how can I use interruptableFuture to stop composed futures? For example
val f = Future {
// blocking interruptable computation
}.map(res => {
// one more blocking interruptable computation
})
How can I cancel future f?
could you explain the point behind passing Future to fun:
"fun: Future[T] => T"
instead of having just:
"fun: => T"
?
@minisaw Because when that Future is completed, the code knows that it has been interrupted, this is important in the case where the logic uses multiple threads underneath and you want to be able to propagate the interruption signal across them all (Thread.interrupted() is only for a single Thread.)
I think that this implementation is not easy to use. And if call the 'cancel' method was before actual starting the task execution, then the task will not be canceled and will be executed. I tried to fix these moments here https://gist.github.com/Tolsi/1c81840b6f132b8f69c2
@Tolsi You should introspect the Future provided to the function to determine whether you want to run or not.
I've updated the code, to only report successful cancellation if both interruption AND completion is successful