Created
December 12, 2020 15:25
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finding nth term of fibonacci(1, 1, 2, 3, ...) in O(logn) time complexity
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#include<bits/stdc++.h> | |
#define MOD 1000000007 | |
map<long long, long long> dp; | |
long long ans(long long n){ | |
if(n<=2) { | |
dp[n]=1; | |
return dp[n]; | |
} | |
if(dp[n]) return dp[n]; | |
if(n%2==0){ | |
long long k = n/2; | |
dp[n] = (((((long long)2*ans(k-1))%MOD + ((long long)ans(k))%MOD)%MOD)*ans(k))%MOD; | |
// formula in even case of n | |
// F_n = (2*F_n/2-1 + F_n/2)*F_n/2 | |
} else { | |
long long k = (n+1)/2; | |
dp[n] = (((long long)ans(k)*ans(k))%MOD + ((long long)ans(k-1)*ans(k-1))%MOD)%MOD; | |
// formula in odd case of n | |
// F_n = (F_(n+1)/2 ^2) + (F_(n+1)/2-1 ^2) | |
} | |
return dp[n]%MOD; | |
} |
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