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December 16, 2015 05:09
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PHP code to display data from our cities database in JSON format. This is the companion code to my iOS Tutorial on loading data from an external database into a table view on YouTube. Youtube channel: www.youtube.com/vtkurup/
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<?php | |
/*************************************************************** | |
Description: City data in JSON. | |
Developer: Vishal Kurup | |
***************************************************************/ | |
$host = "abc12345"; //Your database host server | |
$db = "abc12345"; //Your database name | |
$user = "abc12345"; //Your database user | |
$pass = "abc12345"; //Your password | |
$connection = mysql_connect($host, $user, $pass); | |
//Check to see if we can connect to the server | |
if(!$connection) | |
{ | |
die("Database server connection failed."); | |
} | |
else | |
{ | |
//Attempt to select the database | |
$dbconnect = mysql_select_db($db, $connection); | |
//Check to see if we could select the database | |
if(!$dbconnect) | |
{ | |
die("Unable to connect to the specified database!"); | |
} | |
else | |
{ | |
$query = "SELECT * FROM cities"; | |
$resultset = mysql_query($query, $connection); | |
$records = array(); | |
//Loop through all our records and add them to our array | |
while($r = mysql_fetch_assoc($resultset)) | |
{ | |
$records[] = $r; | |
} | |
//Output the data as JSON | |
echo json_encode($records); | |
} | |
} | |
?> |
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