Created
July 23, 2015 05:37
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Prints a 2D array in Spiral Order
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def spiralOrder(A): | |
result = [] | |
T = 0 | |
B = len(A) - 1 | |
L = 0 | |
R = len(A[0]) -1 | |
dir = 0 | |
while T <= B and L <= R : | |
if dir == 0 : | |
for i in range(L, R+1) : | |
result.append(A[T][i]) | |
T = T + 1 | |
dir = 1 | |
elif dir == 1 : | |
for i in range(T, B + 1) : | |
result.append(A[i][R]) | |
R = R - 1 | |
dir = 2 | |
elif dir == 2 : | |
for i in range(R , L - 1 , -1) : | |
result.append(A[B][i]) | |
B = B -1 | |
dir = 3 | |
elif dir == 3 : | |
for i in range(B, T - 1, -1) : | |
result.append(A[i][L]) | |
L = L + 1 | |
dir = 0 | |
return result | |
A = ((1,2,3),(4, 5, 6)) | |
print(spiralOrder(A)) //will print [1, 2, 3, 6, 5, 4] |
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