Created
August 5, 2015 19:22
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Given a column title as appears in an Excel sheet, return its corresponding column number.
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| def titleToNumber(self, A): | |
| alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" | |
| num = 0 | |
| for i in range(len(A)) : | |
| num += (alphabet.index(A[i]) + 1) * (26 ** (len(A) - i - 1) ) | |
| return num | |
| #A -> 1 | |
| #B -> 2 | |
| #C -> 3 | |
| #... | |
| #Z -> 26 | |
| #AA -> 27 | |
| #AB -> 28 |
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