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Source Bash file using a Python function
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import os | |
from subprocess import Popen, PIPE | |
import pickle | |
PYTHON_DUMP_ENVIRON = """\ | |
import sys | |
import os | |
import pickle | |
data = pickle.dumps(os.environ) | |
stdout = os.fdopen(sys.stdout.fileno(), "wb") | |
stdout.write(data) | |
""" | |
def source_bash_file(path): | |
bash_cmds = [ | |
"source '%s'" % path, | |
"python -c '%s'" % PYTHON_DUMP_ENVIRON, | |
] | |
p = Popen(['bash', '-c', '&&'.join(bash_cmds)], stdout=PIPE) | |
stdout, _ = p.communicate() | |
if stdout: | |
environ = pickle.loads(stdout) | |
for k, v in environ.items(): | |
os.environ[k] = v |
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Thanks for this gist! I had to modify line 11 in a more recent version of python to:
data = pickle.dumps(dict(os.environ))
in order to make it work. Apparently os.environ is now wrapped in a class that cannot be pickled.