PHP: get image src attribute (regular expression)

image-src-regexpr.php

<?php
// Source: http://goo.gl/qyLFbg

$html = '<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />';

preg_match( '@src="([^"]+)"@' , $html, $match );

$src = array_pop($match);

// will return /images/image.jpg
echo $src;

Hy, in my case i have a html file which has store the view source of url and then i want to Get all 'img' tages with 'alt' from html file ,so what i do for this....

thanks in advance.

Hy, in my case i have a html file which has store the view source of url and then i want to Get all 'img' tages with 'alt' from html file ,so what i do for this....

thanks in advance.

$html = '
    <img border="0" src="/images/image1.jpg" alt="Image" width="100" height="100" />
    <img border="0" src="/images/image2.jpg" alt="Image" width="100" height="100" />
    <img border="0" src="/images/image3.jpg" alt="Image" width="100" height="100" />
    ';

$get_Img_Src = '/<img[^>]*src=([\'"])(?<src>.+?)\1[^>]*>/i'; //for get img src path only...

preg_match_all($get_Img_Src, $html, $result); 
echo $result['src'][0];
echo $result['src'][1];

OR

$get_Img_Src = '/<img[^>]*src=([\'"])(?<src>.+?)\1[^>]*alt=([\'"])(?<alt>.+?)\2*>/i'; //for get img src path & alt text also

preg_match_all($get_Img_Src, $html, $result); 
echo $result['src'][0];
echo $result['src'][1];
echo $result['alt'][0];
echo $result['alt'][1];

Hola, es mi caso funciono a la perfección, gracias. Saludos.