Created
April 3, 2012 18:04
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Convert CIDR notation to regex
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#!/usr/bin/python | |
''' Not my script, found on the Internet, and rediscovered on my hard drive | |
''' | |
import sys | |
def cidr_to_regex(cidr): | |
ip, prefix = cidr.split('/') | |
base = 0 | |
for val in map(int, ip.split('.')): | |
base = (base << 8) | val | |
shift = 32 - int(prefix) | |
start = base >> shift << shift | |
end = start | (1 << shift) - 1 | |
def regex(lower, upper): | |
if lower == upper: | |
return str(lower) | |
from math import log10 | |
exp = int(log10(upper - lower)) | |
delta = 10 ** exp | |
if lower == 0 and upper == 255: | |
return "\d+" | |
if delta == 1: | |
val = "" | |
for a, b in zip(str(lower), str(upper)): | |
if a == b: | |
val += str(a) | |
elif (a, b) == ("0", "9"): | |
val += '\d' | |
elif int(b) - int(a) == 1: | |
val += '[%s%s]' % (a, b) | |
else: | |
val += '[%s-%s]' % (a, b) | |
return val | |
def gen_classes(): | |
floor_ = lambda x: int(round(x / delta, 0) * delta) | |
xs = range(floor_(upper) - delta, floor_(lower), -delta) | |
for x in map(str, xs): | |
yield '%s%s' % (x[:-exp], r'\d' * exp) | |
yield regex(lower, floor_(lower) + (delta - 1)) | |
yield regex(floor_(upper), upper) | |
return '|'.join(gen_classes()) | |
def get_parts(): | |
for x in range(24, -1, -8): | |
yield regex(start >> x & 255, end >> x & 255) | |
return '^%s$' % r'\.'.join(get_parts()) | |
for line in sys.stdin.readlines(): | |
print cidr_to_regex( line ) | |
I suggest checking out this derived version:
https://gist.github.com/tom-knight/1b5e0dcf39062af8910e
I dug down through all the forks and found this one to be the most promising. Hope this saves other people time!
Javascript version: https://gist.github.com/radu-c/df0408cb55de758e03b7568cc05f1865
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i think this line should be
https://gist.github.com/petermblair/2294250#file-cidr2regex-py-L51