Created
November 26, 2013 13:59
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Mergesort implementatie
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#include "as1_t2.h" | |
#include <stdlib.h> | |
#include <stdio.h> | |
#include <assert.h> | |
#include <string.h> | |
// CONFIGURATION. | |
// Change these to change the type of array msort sorts, or the key it sorts | |
// on. | |
typedef task_t elem; | |
inline unsigned long key(elem** el) { | |
return (*el)->id; | |
} | |
// IMPLEMENTATION FUNCTIONS. | |
// Allocate and clear a bit of memory, failing hard if that doesn't work | |
void* xcalloc(size_t nmemb, size_t size) { | |
void* mem = calloc(nmemb, size); | |
if (mem == NULL) { | |
char* msg = "FATAL: Memory exhausted (tried to allocate %d bytes)\n"; | |
fprintf(stderr, msg, nmemb * size); | |
exit(EXIT_FAILURE); | |
return NULL; | |
} else { | |
return mem; | |
} | |
} | |
// Dump the list of elements in the list to standard output. Useful for | |
// debugging. | |
void msort_dump(elem** elems, int count) { | |
printf("["); | |
for (int i = 0; i < count; i++) { | |
printf("%ld", key(elems + i)); | |
if (i + 1 < count) printf(", "); | |
} | |
printf("]\n"); | |
} | |
// Merge the left and right sublists inside the [first, last) range of elems. | |
void msort_merge(elem** elems, int first, int last) { | |
int count = last - first; | |
int mid = first + (count/2); | |
// Lay down some ground rules. | |
assert(first >= 0); | |
assert(last > first); | |
assert(count >= 2); | |
// Allocate a buffer to put the sorted result in. | |
elem** buf = xcalloc(count, sizeof(elem*)); | |
// Pointers! | |
elem** left = elems + first; | |
elem** center = elems + mid; | |
elem** right = elems + last; | |
elem** a = left; | |
elem** b = center; | |
// While there are elements left to sort... | |
for (int i = 0; i < count; i++) { | |
if (a < center && b < right) { | |
// We have elements both on the left and the right | |
if (key(a) <= key(b)) { | |
// A <= B, so put A in the buffer and advance A | |
buf[i] = *(a++); | |
} else { | |
// B < A, so put B in the buffer and advance B | |
buf[i] = *(b++); | |
} | |
} else if (a < center) { | |
// Trailing elements on the left. Add them. | |
buf[i] = *(a++); | |
} else if (b < right) { | |
// Trailing elements on the right. Add them. | |
buf[i] = *(b++); | |
} else { | |
break; | |
} | |
} | |
// Our buffer has been prepared, copy it over our input. | |
memcpy(elems + first, buf, count * sizeof(elem*)); | |
// Don't need the buffer anymore. | |
free(buf); | |
return; | |
} | |
void msort_range(elem** elems, int start, int end) { | |
// Sanity checking. | |
assert(elems != NULL); | |
assert(start >= 0); | |
assert(end >= start); | |
if (start == end) { | |
// Empty list is already sorted | |
return; | |
} else if (end - start == 1) { | |
// List with one element is already sorted | |
return; | |
} else { | |
// Find out the index of the middle element | |
int mid = start + ((end - start) / 2); | |
// Call ourselves for our left side, our right side, then merge | |
msort_range(elems, start, mid); | |
msort_range(elems, mid, end); | |
msort_merge(elems, start, end); | |
} | |
} | |
void msort(elem** elems, int count){ | |
// Entry point for the merge sort. Sorts the whole list of elems | |
// destructively. | |
msort_range(elems, 0, count); | |
} | |
/* vim: set ts=4 sw=4 noet: */ |
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