Created
July 29, 2019 03:34
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// https://www.geeksforgeeks.org/reverse-a-list-in-groups-of-given-size/ | |
class Node { | |
constructor(val, next) { | |
this.val = val; | |
this.next = next; | |
} | |
} | |
function printList(head) { | |
let tmp = head; | |
let arr = []; | |
while (tmp) { | |
arr.push(tmp.val); | |
tmp = tmp.next; | |
} | |
return arr; | |
} | |
function reverseK(head, K) { | |
let tmp = head; | |
let next; | |
let prev; | |
let count = 0; | |
while (tmp && count < K) { | |
next = tmp.next; | |
tmp.next = prev; | |
prev = tmp; | |
tmp = next; | |
count++; | |
} | |
if (next) { | |
head.next = reverseK(next, K); | |
} | |
return prev; | |
} | |
const ex1Head = new Node(1, new Node(2, | |
new Node(3, new Node(4, new Node(5, new Node(6, new Node(7, new Node(8)))))))); | |
const res = reverseK(ex1Head, 3); | |
console.log(printList(res).join(',') === '3,2,1,6,5,4,8,7'); |
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