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January 1, 2016 04:39
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Reverse Integer
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/** | |
* Reverse digits of an integer. | |
Example1: x = 123, return 321 | |
Example2: x = -123, return -321 | |
Have you thought about this? | |
Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! | |
1. If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100. | |
2. Did you notice that the reversed integer might overflow? | |
Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases? | |
3. Throw an exception? | |
Good, but what if throwing an exception is not an option? You would then have to re-design the function (ie, add an extra parameter). | |
*/ | |
public class Solution{ | |
public int reverse(int x) { | |
int res = 0; | |
int lastDigit = 0; | |
boolean isNeg = x < 0 ? true : false; | |
x = Math.abs(x); | |
while(x > 0){ | |
lastDigit = x % 10; | |
if(res > Integer.MAX_VALUE / 10) return 0; | |
res = lastDigit + res * 10; | |
x = x / 10; | |
} | |
if(isNeg) res = -res; | |
return res; | |
} | |
} |
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