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January 1, 2016 12:38
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Merge Two Sorted Lists
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| /** | |
| * Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. | |
| */ | |
| /** | |
| * Definition for singly-linked list. | |
| * public class ListNode { | |
| * int val; | |
| * ListNode next; | |
| * ListNode(int x) { | |
| * val = x; | |
| * next = null; | |
| * } | |
| * } | |
| */ | |
| public class Solution { | |
| public ListNode mergeTwoLists(ListNode l1, ListNode l2) { | |
| ListNode head = new ListNode(0); | |
| ListNode curr = head; | |
| while(l1 != null && l2 != null){ | |
| if(l1.val <= l2.val){ | |
| curr.next = l1; | |
| l1 = l1.next; | |
| }else{ | |
| curr.next = l2; | |
| l2 = l2.next; | |
| } | |
| curr = curr.next; | |
| } | |
| if(l1 != null) | |
| curr.next = l1; | |
| else if(l2 != null) | |
| curr.next = l2; | |
| return head.next; | |
| } | |
| } |
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| public class Solution { | |
| public ListNode mergeTwoLists(ListNode l1, ListNode l2) { | |
| if(l1 == null) | |
| return l2; | |
| if(l2 == null) | |
| return l1; | |
| ListNode head = new ListNode(0); | |
| if(l1.val <= l2.val){ | |
| head = l1; | |
| head.next = mergeTwoLists(l1.next, l2); | |
| }else{ | |
| head = l2; | |
| head.next = mergeTwoLists(l2.next, l1); | |
| } | |
| return head; | |
| } | |
| } | |
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