pairing_exercise.md

First level

Filter all names by their first character of the given array.

["Hans", "Mike", "Fabian", "Anna"]

• "H" returns ["Hans"]
• "M" returns ["Mike"]
• "F" returns ["Fabian"]

const filterMembers = (members, search) => { // todo }

Second level

Enhance the previous example and filter all names by any character

• "A" returns ["Hans", "Fabian", "Anna"]
• "i" returns ["Mike", "Fabian"]

Third level

The API endpoint changed. Instead of returning a list of strings it now returns a list of objects. The behaviour should stay the same as in the previous exercise.

[{ first: "Hans" }, { first: "Mike" }, { first: "Fabian" }, { first: "Anna" }]

• "A" returns [{ first: "Hans"}, { first: "Fabian" }, { first: "Anna" }]
• "i" returns [{ first: "Mike" }, { first: "Fabian" }]

Fourth level

The API Endpoint now returns the last name as well. Our filter function should filter by first and last name.

[
  { first: "Hans", last: "Müller" },
  { first: "Mike", last: "Eibensteiner" },
  { first: "Fabian", last: "Hofer" },
  { first: "Anna", last: "Huber" },
]

possible_solution.js

const includedInString = (stringToBeSearchedIn, search) =>
  (stringToBeSearchedIn || '').toLowerCase().indexOf((search || '').toLowerCase()) !== -1;

const searchMember = (search) => (member) => Object.keys(member)
  .some((key) => includedInString(member[key], search));

const filterMembers = (members = [], search = '') =>
  members.filter(searchMember(search));