2 ajax requests?

<div id="container">
    <input type="hidden" id="var" value="wenbert"/>
    <input type="button" id="thebutton" value="Click"/>
</div>
<script type="text/javascript">
$(document).ready(function() {
<script type="text/javascript">
$(document).ready(function() {
	$("#thebutton").click(function(){
	    call_ajax1();
	    call_ajax2();
	});

	function call_ajax1(){
		$.post("/books/action1/", 
			{
				csrfmiddlewaretoken: $("input[name='csrfmiddlewaretoken']").val(),
				var: $("#var").val(),
			},
			function(data){
				if(data['success']){
					// show results to DOM here
				} else {
					console.log("error");
					return false;
				}
			},
			"json"
		);
	}
	
	function call_ajax2(){
		$.post("/books/action2/", 
			{
				csrfmiddlewaretoken: $("input[name='csrfmiddlewaretoken']").val(),
				var: $("#var").val(),
			},
			function(data){
				if(data['success']){
					// show results to DOM here
				} else {
					console.log("error");
					return false;
				}
			},
			"json"
		);
	}

});
</script>
});

lets say sa call_ajax1() ang return i-output nimo sa "div_a" then ang return sa call_ajax2() imu i-out sa "div_zzz"....ga-libog kay imu g-huna2x ra imu g-over complicate...

if dili gani madala ani, tell me unsa imu gusto mahitabo...

What if both $.post()s point to the same url? /books/search/..

Ako plano kay ig-search sa title/author, mag search ko sa local database for the book using Book.objects.filter(...) in the view and at the same time mg-search pd ko sa Amazon. Kay mas dali man m-kuha ang naa sa local database, para m-una og display nya m-apas lng Amazon results.

pwede raman na sa usa ka view and then ang ireturn nimo from localdb sulod nimo ug usa ka list then ang i-return nimo gkan sa amazon sulod pd nimo ug usa ka list.

just search the localdb first aron mas kusog then ang amazon dayon sunod...