Created
September 3, 2009 19:24
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Levenshtein distance algorithm in Ruby
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class Distance | |
attr_accessor :s1, :s2 | |
def initialize(str1,str2) | |
@s1 = str1 | |
@s2 = str2 | |
end | |
def lev_distance | |
m = @s1.length | |
n = @s2.length | |
d = Array.new(m+1) { Array.new(n+1) {0} } | |
for i in 0..m | |
d[i][0] = i | |
end | |
for j in 0..n | |
d[0][j] = j | |
end | |
for j in 1..n | |
for i in 1..m | |
if (@s1[i-1] == @s2[j-1]) then | |
cost = 0 | |
else | |
cost = 1 | |
end | |
d[i][j] = [d[i-1][j]+1, d[i][j-1]+1, d[i-1][j-1] + cost].min | |
end | |
end | |
return d[m][n] | |
end | |
end | |
s1 = "kitten" | |
s2 = "sitting" | |
puts "Edit Distance between #{s1} and #{s2} is: " + Distance.new(s1,s2).lev_distance.to_s |
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