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one pass through records (for mean and variance); annoyingly proper definition of median
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# Run the given block +num+ times and then print out the mean, median, min, | |
# max, and stddev of the run. For example: | |
# | |
# irb> stats(10) { sleep(rand / 100) } | |
# mean: 5.99ms | |
# median: 6.76ms | |
# min: 1.49ms | |
# max: 9.28ms | |
# stddev: 2.54ms | |
def stats(num) | |
records = [] | |
num.times do | |
t0 = Time.now | |
yield | |
records << (Time.new-t0) | |
end | |
srecords = records.sort | |
num = records.size | |
n, mean, m2 = records.inject([0,0.0,0.0]) do | |
|acc, r| | |
n = acc[0]+1 | |
delta = r-acc[1] | |
mean = acc[1] + (delta/n) | |
m2 = acc[2] + (delta * (r-mean)) | |
[n, mean, m2] | |
end | |
var = m2/n | |
puts "mean: %1.2fms" % (mean * 1000) | |
puts "median: %1.2fms" % ((num % 2 == 1) ? (srecords[num/2] * 1000) : ((srecords[num/2]+(srecords[num/2-1])/2) * 1000)) | |
puts "min: %1.2fms" % (srecords.first * 1000) | |
puts "max: %1.2fms" % (srecords.last * 1000) | |
puts "stddev: %1.2fms" % (Math.sqrt(var) * 1000) | |
end |
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