[FrogJump] Count minimal number of jumps from position X to Y #hackerrank #codility #python

FrogJump.py

"""
Task description
A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D.

Count the minimal number of jumps that the small frog must perform to reach its target.

Write a function:

def solution(X, Y, D)

that, given three integers X, Y and D, returns the minimal number of jumps from position X to a position equal to or greater than Y.

For example, given:

  X = 10
  Y = 85
  D = 30
the function should return 3, because the frog will be positioned as follows:

after the first jump, at position 10 + 30 = 40
after the second jump, at position 10 + 30 + 30 = 70
after the third jump, at position 10 + 30 + 30 + 30 = 100
Write an efficient algorithm for the following assumptions:
"""

import math

def solution(X, Y, D):
    # write your code in Python 3.6
    length = (Y - X)
    jumps = length / D
    
    result = math.ceil(jumps)
    
    return result