Created
April 9, 2013 03:55
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取两个HTML节点最近的公共父节点
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function getCommonParent(el1,el2){ | |
var parents1 = []; | |
var el = el1; | |
while(el) { | |
parents1.unshift(el); | |
el = el.parentNode; | |
} | |
var parents2 = []; | |
var el = el2; | |
while(el) { | |
parents2.unshift(el); | |
el = el.parentNode; | |
} | |
var i = 0; | |
while(i<parents1.length && i<parents2.length && parents1[i+1] == parents2[i+1]) | |
i++; | |
return parents1[i]; | |
} |
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再来一段使用的标准compareDocumentPosition的,把代码修改得简洁了一点。