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@wintercn
Created April 9, 2013 03:55
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取两个HTML节点最近的公共父节点
function getCommonParent(el1,el2){
var parents1 = [];
var el = el1;
while(el) {
parents1.unshift(el);
el = el.parentNode;
}
var parents2 = [];
var el = el2;
while(el) {
parents2.unshift(el);
el = el.parentNode;
}
var i = 0;
while(i<parents1.length && i<parents2.length && parents1[i+1] == parents2[i+1])
i++;
return parents1[i];
}
@cuixiping
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再来一段使用的标准compareDocumentPosition的,把代码修改得简洁了一点。

function getCommonParent(a,b){
    var c = a.compareDocumentPosition(b);
    if(c & 8){
        return b.parentNode;
    }else if(c & 16){
        return a.parentNode;
    }else if(c & 6){
        while(!(8 & a.compareDocumentPosition(b=b.parentNode)));
        return b;
    }
    return null;
}

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