FizzBuzz in ES6 with no loops

fizzbuzz.js

// first version
var fizzBuzzN = n => { 
  if (n % 15 == 0) return "FizzBuzz";
  if (n % 3 == 0) return "Fizz";
  if (n % 5 == 0) return "Buzz";
  return n;
}

// second version -- single divisibility test, no repeat of 3 and 5 cases
// 3 and 5 
var fizzBuzzN = n => ([[3,"Fizz"],[5,"Buzz"]]).reduce((s,x)=> n % x[0] == 0 ? s+x[1] : s, "") || n

[... Array(100).keys()].map(i => i+1).map(fizzBuzzN).join('\n')