Simple Active Directory authentication with Spring LDAP

context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ldap="http://www.springframework.org/schema/ldap"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/ldap http://www.springframework.org/schema/ldap/spring-ldap.xsd">

    <ldap:context-source
            url="ldap://adserver1.yourcompany.com:389, ldap://adserver2.yourcompany.com:389"
            base="dc=yourcompany,dc=com"
            username="...,dc=yourcompany,dc=com"
            password="secret"
            referral="follow"/>

    <ldap:ldap-template id="ldapTemplate" />

</beans>

Example.java

import static org.springframework.ldap.query.LdapQueryBuilder.query;

import org.springframework.ldap.core.LdapTemplate;
import org.springframework.ldap.AuthenticationException;

public class Example {
  @Autowired
  LdapTemplate ldapTemplate;
  
  public boolean authenticate(String uid, String credentials) {
    try {
      ldapTemplate.authenticate(query().where("uid").is(uid), credentials);
      return true;
    } catch (AuthenticationException e) {
      LOG.error("Login failed", e);
      return false;
    }
  }
}

pom.xml

        <dependency>
            <groupId>org.springframework.ldap</groupId>
            <artifactId>spring-ldap-core</artifactId>
            <version>2.0.1.RELEASE</version>
        </dependency>