Created
May 25, 2012 13:38
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Xerxes solutions to typeclass problems
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data List a = Elem a | List [List a] deriving (Show) | |
flatten' :: List a -> [a] | |
flatten' (Elem x) = [x] | |
flatten' (List (x:xs)) = flatten' x ++ flatten' (List xs) | |
flatten' (List []) = [] | |
data Tree a = Empty | Node a (Tree a) (Tree a) | |
deriving (Eq, Show, Read) | |
treeInsert :: Ord a => Tree a -> a -> Tree a | |
treeInsert Empty a = Node a Empty Empty | |
treeInsert tree@(Node v l r) a | |
| v > a = Node v (treeInsert l a) r | |
| v < a = Node v l (treeInsert r a) | |
| v == a = tree | |
treeFromList :: Ord a => [a] -> Tree a | |
--treeFromList [] = Empty | |
--treeFromList (x:xs) = treeInsert (treeFromList xs) x | |
--treeFromList xs = foldr (\x acc -> treeInsert acc x) Empty xs | |
--treeFromList = foldr (\x acc -> flip treeInsert x acc) Empty | |
treeFromList = foldr (flip treeInsert) Empty | |
class Mappable m where | |
mmap :: (a -> b) -> m a -> m b | |
instance Mappable List where | |
mmap f (Elem x) = Elem (f x) | |
mmap f (List xs) = List(map (mmap f) xs) | |
mmap' :: (a->b) -> List a -> List b | |
mmap' f (Elem x) = Elem (f x) | |
--mmap' f (List []) = List [] | |
--mmap' f (List (x:xs)) = List (mappedFirst : mappedRest) | |
-- where | |
-- mappedFirst = mmap' f x | |
-- mappedRest = map (\y -> mmap' f y) xs | |
--mmap' f (List xs) = List(map (\y -> mmap' f y) xs) | |
mmap' f (List xs) = List(map (mmap' f) xs) | |
instance Mappable Tree where | |
mmap f Empty = Empty | |
mmap f (Node v l r) = Node (f v) (mmap f l) (mmap f r) | |
increaseAll :: (Enum a, Mappable m) => m a -> m a | |
increaseAll xs = mmap succ xs |
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