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Simple python Linked List implementation
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class Node: | |
def __init__(self, value, next_item=None): | |
self.value = value | |
self.next = next_item | |
class LinkedList: | |
storage = [] | |
def __init__(self): | |
self.first = None | |
self.last = None | |
self.length = 0 | |
def __str__(self): | |
self.values = [] | |
self.iter(lambda _, current: self.values.append(str(current.value))) | |
if self.length: | |
return ' -> '.join(self.values) | |
else: | |
return 'Empty list' | |
def iter(self, callback): | |
prev = None | |
current = self.first | |
while True: | |
callback(prev, current) | |
if current.next != None: | |
prev = current | |
current = current.next | |
else: | |
break | |
return current | |
def add(self, value): | |
self.length += 1 | |
if not self.first: | |
self.first = self.last = Node(value) | |
else: | |
item = self.first | |
while item.next != None: | |
item = item.next | |
item.next = self.last = Node(value) | |
def remove(self, value): | |
def remove(prev, current): | |
self.length -= 1 | |
if current.value == value: | |
if prev: | |
prev.next = current.next | |
else: | |
if current.next: | |
self.first = current.next | |
else: | |
self.first = self.last = None | |
self.iter(remove) | |
a = LinkedList() | |
a.add(1) | |
a.add(2) | |
a.add(3) | |
a.add(10) | |
print a |
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