Created
April 26, 2021 12:06
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Google Code Jam -- Rounding Error -- Solution in Python
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# usage: (python3 a.py < a.in) > a.out | |
import time, sys, inspect, platform | |
print = lambda *a, **k: __builtins__.print(str(inspect.currentframe().f_back.f_lineno)+':', | |
*a, file=sys.stderr, **k) if platform.node() in ['surfux', 'ssd'] else ... | |
#--------------------------------------------- | |
''' | |
i know this is 'sort-by-goodness' | |
so just add to the one closest to .5 ? | |
i.e. .4 > .3 > .2 > .1 > .0 > .9 > .8 > .7 > .6 > .5 | |
round() in Python is broken | |
>>> round(1.5) | |
2 | |
>>> round(2.5) # ????? | |
2 | |
>>> round(3.5) | |
4 | |
-> rounds to EVEN | |
-> use custom round instead | |
''' | |
import heapq | |
round = lambda x: int(x + .5) | |
def run(data): | |
n, data = data | |
left = n - sum(data) | |
data = data + [0] * left | |
# .499 gets mapped to -.999 (first) and .501 to -.001 (last) | |
fractional_key = lambda x: (.5 + x/n * 100) % 1 | |
# heap is a great data structure for inserting keys and getting the min | |
data = [(-fractional_key(d), d) for d in data] | |
heapq.heapify(data) | |
for _ in range(left): | |
# add 1 to the numerator (number of people) and put back into heap | |
__, num_ppl = heapq.heappop(data) | |
updated = (-fractional_key(num_ppl+1), num_ppl+1) | |
heapq.heappush(data, updated) | |
return sum([round(num_ppl/n * 100) for _, num_ppl in data]) | |
#--------------------------------------------- | |
def read_case(): | |
n, _ = [int(k) for k in list(input().split())] | |
return (n, [int(k) for k in list(input().split())]) | |
for i in range(int(input())): | |
outstr = 'Case #'+str(i+1)+': '+str(run(read_case())) | |
print(outstr, ' @ t =', time.clock()) | |
__builtins__.print(outstr) |
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