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intuitive string-to-type conversion in C++ using user defined conversion; use `int i = val("22");`
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| #include "headers.h" | |
| struct Val_t { | |
| const std::string_view s; | |
| template<typename T> | |
| operator T() const { return S<T>::cast(s); } | |
| // can't have partial function specialization, | |
| // hence we use an intermediate structure | |
| template<typename T> | |
| struct S { | |
| static T cast(const std::string_view &s); | |
| }; | |
| }; | |
| using namespace std; | |
| template<> int Val_t::S<int>::cast(const string_view &s) { return 22; } | |
| template<typename T> | |
| //#define IF_ONLY_I_COULD_WRITE | |
| #ifdef IF_ONLY_I_COULD_WRITE | |
| // error C2244: 'Val_t::S<std::vector<T,std::allocator<_Ty>>>::cast': unable to match function definition to an existing declaration | |
| auto Val_t::S<vector<T>>::cast(const string_view &s) { | |
| return vector<T>{ 1, 2, 4 }; | |
| } | |
| #else | |
| struct Val_t::S<vector<T>> { | |
| static auto Val_t::S<vector<T>>::cast(const string_view &s) { | |
| return vector<T>{ 1, 2, 4 }; | |
| } | |
| }; | |
| #endif | |
| int main() | |
| { | |
| int i = Val_t{"22"}; | |
| assert(i == 22); | |
| vector<int> ints = Val_t{"1, 2, 4"}; | |
| assert((ints == vector<int>{ 1, 2, 4 })); | |
| } |
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| #include <iostream> | |
| #include <string> | |
| #include <stdexcept> | |
| #include <vector> | |
| #include <iterator> | |
| #include <algorithm> | |
| #include <numeric> | |
| #include <cassert> | |
| #include <string_view> |
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