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151. Reverse Words in a String
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/* | |
Given an input string, reverse the string word by word. | |
Example: | |
Input: "the sky is blue", | |
Output: "blue is sky the". | |
Note: | |
A word is defined as a sequence of non-space characters. | |
Input string may contain leading or trailing spaces. However, your reversed string should not contain leading or trailing spaces. | |
You need to reduce multiple spaces between two words to a single space in the reversed string. | |
Follow up: For C programmers, try to solve it in-place in O(1) space. | |
Copyright © 2018 LeetCode | |
*/ | |
#include <iostream> | |
#include <functional> | |
#include <vector> | |
#include <algorithm> | |
#include <cctype> | |
std::string reverseWords(std::string &s) { | |
auto sourceSize = s.size(); | |
std::string resultStr; | |
resultStr.reserve(sourceSize); | |
std::string str; | |
str.reserve(sourceSize / 2 ); | |
auto concatStr = [](std::string &str1, std::string &str2)-> std::string { | |
if (str2.length() == 0) | |
return str1; | |
return str1 + " " + str2; | |
}; | |
bool prevSymbol = false; | |
for (auto &c : s) { | |
bool isSpace = std::isspace(c) != 0; | |
if (isSpace && prevSymbol) { | |
resultStr = concatStr(str, resultStr); | |
str = ""; | |
prevSymbol = false; | |
continue; | |
} | |
else if (isSpace) | |
{ | |
continue; | |
} | |
prevSymbol = true; | |
str += c; | |
} | |
if (str.length() != 0) { | |
resultStr = concatStr(str, resultStr); | |
} | |
return resultStr; | |
} | |
void checkValue(std::string input, std::string expected) | |
{ | |
auto result = reverseWords(input); | |
if (result != expected) { | |
throw new std::runtime_error("Failed on \"" + input + "\" Expected: " + expected); | |
} | |
} | |
int main() | |
{ | |
// Defaults from task | |
checkValue("the sky is blue", "blue is sky the"); | |
checkValue(" the sky is blue ", "blue is sky the"); | |
return 0; | |
} | |
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