Created
November 19, 2012 12:04
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5.txt
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inorder (reflect t) = rev (inorder t) について | |
(i) t = Lf の時、成り立つことを示せばよい。 | |
<左辺> = inorder (reflect Lf) | |
= inorder Lf reflectの定義より | |
= [] inorderの定義より | |
<右辺> = rev (inorder Lf) | |
= rev Lf inorderの定義より | |
= [] revの定義より | |
よって、両辺が同じになったので、成り立つ。 | |
(ii) t = t1, t2で成り立つと仮定して、t = Br (v, t1, t2)が成り立つことを示せばよい。 | |
<左辺> = inorder (reflect (Br v, t1, t2)) | |
= inorder (Br v, (reflect t2), (reflect t1)) reflectの定義より | |
= (inorder (reflect t2)) @ v @ (inorder (reflect t1)) inorderの定義より | |
<右辺> = rev (inorder (Br v, t1, t2)) | |
= rev ( (inorder t1) @ v @ (inorder t2) ) inorderの定義より | |
= (rev (inorder t2)) @ v @ (rev (inorder t1)) revの定義より | |
= (inorder (reflect t2)) @ v @ (inorder (reflect t1)) 仮定より | |
よって、成り立つ | |
(i), (ii)より、成り立つ。 |
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