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November 29, 2017 03:58
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break陷阱
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func foo_while() { | |
sum := 0 | |
for { | |
// todo 为什么不是100而是101 | |
//sum++ | |
//fmt.Printf("sum的值是%v\n",sum) | |
fmt.Printf("比较前的值%v\n",sum) | |
if sum > 100 { | |
fmt.Printf("\n sum>100 %v\n",sum) | |
break | |
} | |
fmt.Printf("sum++前的值\t%v\n",sum) | |
sum++ | |
fmt.Printf("sum++后的值是%v\n",sum) | |
} | |
fmt.Printf("\nsum的值应该是100 是吗? %v\n", sum) | |
} |
Author
yanjinbin
commented
Nov 29, 2017
•
其实java里面也是一样的
所以并不是个break trick
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