Last active
March 26, 2018 18:18
-
-
Save yarjor/c64a5020019be1877d5f28bda6a2f3ff to your computer and use it in GitHub Desktop.
[Break repeating-key XOR encryption] #crypto #xor
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| from break_single_key import break_single_key | |
| def get_block(msg, length, index=0): | |
| return msg[length * index : length * (index + 1)] | |
| def break_repeating_by_keysize(msg, keysize): | |
| blocks = [get_block(msg, keysize, i) for i in xrange(len(msg) / keysize)] | |
| transposed_blocks = zip(*blocks) | |
| full_key = '' | |
| for trans in transposed_blocks: | |
| _, key = break_single_key(trans, True) | |
| full_key += key | |
| return repeating_key_xor(msg, full_key), full_key | |
| def guess_keysize(msg, size_range=range(2, 45), return_options=5): | |
| key_size_hamming = [] | |
| for keysize in size_range: | |
| blocks = [get_block(msg, keysize, i) for i in xrange(len(msg) / keysize)] | |
| hammings = [calc_hamming(block, blocks[index*2 +1]) / float(keysize) for index, block in enumerate(blocks[::2]) if index*2 < len(blocks)] | |
| avg_ham = sum(hammings) / float(len(hammings)) | |
| key_size_hamming.append((keysize, avg_ham)) | |
| key_size_hamming.sort(key=lambda x: x[1]) | |
| return key_size_hamming[:return_options] | |
| def break_repeating_key(msg, quality_test, size_range=range(2, 45), range_options=5): | |
| optional_sizes = guess_keysize(msg, size_range, range_options) | |
| possible_solutions = [break_repeating_by_keysize(msg, i) for i in optional_sizes] | |
| possible_solutions.sort(key=lambda x: quality_test(x[0])) | |
| return possible_solutions[0] |
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| def break_single_key(msg, quality_test, return_key=False): | |
| possible_outputs = [] | |
| for key in map(chr, xrange(256)): | |
| out = repeating_key_xor(msg, key) | |
| possible_outputs.append((key, out)) | |
| possible_outputs.sort(key=lambda x: quality_test(x[-1])) | |
| res = possible_outputs[0] | |
| if return_key: | |
| return res[::-1] | |
| return res[1] |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment