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@yassu
Created July 8, 2015 23:04
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\documentclass{article}
\usepackage{amsmath, amssymb}
\usepackage{amsthm}
\newcommand{\RR}{\mathbf{R}}
\begin{document}
We define diffeomorphism $\phi \colon \RR^2 \to \RR^2$ by identify:
\[
\phi(x, y) = (x, y).
\]
Then jacobian of $\phi$ is identity matrix:
\begin{align*}
J_\phi = \begin{pmatrix}
1 && 0 \\
0 && 1
\end{pmatrix}.
\end{align*}
\end{document}
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