Cron job check mysql for run php script and run every 5 second

gistfile1.txt

# check mysql for run php script

if [ $(mysql -u MYSQL_USER -pMYSQL_PASSWORD -Bse "SELECT flag FROM DATABASE_NAME.TABLE_NAME where id=1") == "1" ]; then
   curl --silent "http://example.com" >/dev/null 2>&1  
fi



# Cronjob every 5 second 


# first create script
vi /path/to/foo.sh
# copy script, run curl 11 times, press `a` and paste.
curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

curl --silent "http://example.com" >/dev/null 2>&1
sleep 5

# press scape, :wq
# VERY IMPORTANT : add 755 to this .sh file
chmod 755 /path/to/foo.sh
# create crontab
crontab -e
# add to file and save
* * * * * /path/to/foo.sh
# check your jobs
crontab -l