Weather API

node-weather.js

var YQL = require('yql');

var query = new YQL('select * from weather.forecast where (location = 94089)');

query.exec(function(err, data) {
  var location = data.query.results.channel.location;
  var condition = data.query.results.channel.item.condition;
  
  console.log('The current weather in ' + location.city + ', ' + location.region + ' is ' + condition.temp + ' degrees.');
});

weather.js

<script>
  var callbackFunction = function(data) {
    var wind = data.query.results.channel.wind;
    alert(wind.chill);
  };
</script>

<script src="https://query.yahooapis.com/v1/public/yql?q=select wind from weather.forecast where woeid in (select woeid from geo.places(1) where text='chicago, il')&format=json&callback=callbackFunction"></script>

weather.m

// Download the following GitHub repository https://github.com/guilhermechapiewski/yql-ios
// Copy the yql-ios folder to your project

#import "YQL.h";

yql = [[YQL alloc] init];
NSString *queryString = @"select wind from weather.forecast where woeid=2460286";
NSDictionary *results = [yql query:queryString];
NSLog(@"%@",results[@"query"][@"count"]);
NSLog(@"%@",results[@"query"][@"results"]);

weather.php

<?php
    $BASE_URL = "http://query.yahooapis.com/v1/public/yql";

    $yql_query = 'select wind from weather.forecast where woeid in (select woeid from geo.places(1) where text="chicago, il")';
    $yql_query_url = $BASE_URL . "?q=" . urlencode($yql_query) . "&format=json";

    // Make call with cURL
    $session = curl_init($yql_query_url);
    curl_setopt($session, CURLOPT_RETURNTRANSFER,true);
    $json = curl_exec($session);
    // Convert JSON to PHP object
     $phpObj =  json_decode($json);
    var_dump($phpObj);

?>

weather.py

import urllib2, urllib, json
baseurl = "https://query.yahooapis.com/v1/public/yql?"
yql_query = "select wind from weather.forecast where woeid=2460286"
yql_url = baseurl + urllib.urlencode({'q':yql_query}) + "&format=json"
result = urllib2.urlopen(yql_url).read()
data = json.loads(result)
print data['query']['results']

weather.sh

curl https://query.yahooapis.com/v1/public/yql \
   -d q="select wind from weather.forecast where woeid=2460286" \
   -d format=json

For Python 3.x, to get around errors which resulted from the code provided in weather.py:

# Python 2.x
# ...

# Python 3.x
import urllib.parse
import urllib.request
import json

baseurl = "https://query.yahooapis.com/v1/public/yql?"
yql_query = "select wind from weather.forecast where woeid=2460286"
yql_url = baseurl + urllib.parse.urlencode({'q':yql_query}) + "&format=json"
result = urllib.request.urlopen(yql_url).read()
data = json.loads(result)
print data['query']['results']

How does the python code change if I use the OAuth credentials? The yahoo developer site doesn't help.

Important EOL Notice: As of Thursday, Jan. 3, 2019, the weather.yahooapis.com and query.yahooapis.com for Yahoo Weather API will be retired.

Does anybody have any idea how to implement it with new way. Documentation is not much clear.

Hi,
I was using this api
http://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text='location')
but this api in not working any updation or changes in above api.

https://community.openhab.org/t/solved-yahoo-weather-does-not-work-anymore/62583

Hi,
I was using this api
http://query.yahooapis.com/v1/public/yql?q=select * from weather.forecast where woeid in (select woeid from geo.places(1) where text='location')
but this api in not working any updation or changes in above api.